The once a year 30% off Black Friday sale with orders over $20 getting free shipping. Additionally, every order over $10 gets one entry for the chance to win 1 of 10 iPhone X’s.
30% off dbrand Skins & Wraps
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This is part of Black Friday / Cyber Monday deals for 2017
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I would suggest practicing on some cheap screen protectors from eBay til you start to get the hang of it. In my experience the skins are quite forgiving and will allow you to reposition them provided you don’t press too hard or get dust trapped underneath.
Applying dbrand skins shouldn't be too difficult if you follow their steps properly, they have a guide for every product they sell a skin for on their website. I've had a skin on my Nexus 6P since early 2016, and yes the thin layer on the side of the phone is where you most likely will have trouble with over time, especially if you have volume/power buttons on the side. I would suggest you get the full skin for your phone, however see how you go with the front and back as they are usually the easiest ones to install depending on the design of the phone.
+1, just follow their videos and don't take shortcuts. Easy as.
Slickwraps also doing Black Friday deals and giveaways: 60% off no code needed
These guys are always advertising on various Youtube channels…
Found out about them from watching MKBHD's videos, they sponsor a significant amount of videos for a lot of tech YouTuber's :)
I bought the 13" XPS in this deal - https://www.ozbargain.com.au/node/342656
How do I know if the above is a 9350 or 9360 to know if these wrpas fit? I can't see reference to 9350 or 9360 in the PC Specs?
Thanks
They have 40%-50% off every few weeks… how is this a deal in particular?
I struggle with putting screen/glass protectors on my phone as it always ends up being aligned incorrectly or I screw something up. So I've always held off from buying dbrand skins as I'd probably face similar issues.
What's everyone's experience with putting on their dbrand skins onto their phones? Is it really as easy as they make it seem out to be?